$$\lim_{x\rightarrow 0}\frac{\sin x}{x}=1$$


$$\lim_{x\rightarrow 0}\frac{\ln (x+1)}{x}=0$$


$$\lim_{x\rightarrow 0}\frac{\log _\alpha {(x+1)}}{x}=\log _\alpha {e}$$


$$\lim_{x\rightarrow 0}(1+x)^\frac{1}{x}=e$$


$$\lim_{x\rightarrow 0}\frac{(\alpha ^x-1)}{x}=\ln \alpha$$


$$\lim_{x\rightarrow 0}x^x=1$$


2010-12-09 • Просмотров [ 771 ]